Archive+Puzzles+81+to+100

Question 100 - Alton

What three digit number is 29 times as large as its last two digits?

Solution 100 725~Alex (Fuck you Alton you stole the 100th question!) Correct. ~ Alton

Question 99 - Alton A worker is to perform work for you for seven straight days. In return for his work, you will pay him 1/7th of a bar of gold per day. The worker requires a daily payment of 1/7th of the bar of gold. What is the fewest number of cuts to the bar of gold that will allow you to pay him 1/7th each day? (Please write out your solution and explain why.)

Solution 99 zero, u could just pay him the entire bar in the end. ~Alex No, you must pay him 1/7th each day. Read the question. ~ Alton 6~Alex Wrong. Try again. =P ~ Alton So the worker is to perform work for u for 7 straight days. In return, you pay him 1/7 a day. In one week, you pay him the entire bar. So this means that there must be 7 pts. 1 cut: 2 pts 2 cut: 3 pts 4 cut: 5 pts 6 cut: 7 pts. Therefore, you cut the bar 6 times(make sure it is at equal proportions, that is, if the bar is 14 cm long, make sure each cut is exactly 2 cm from each other and the 1st and last cuts must be 2 cm from the edge) equally to give him the money. The end~A very pissed off guy.
 * sigh* you asshole

2 cuts to make it 1, 2 and 4 1st day you give the 1part 2nd day you take it back and give him the 2 part 3rd day you give him 1 part so on... ~Garett Garett is correct. ~ Alton
 * is launching an objection* the point is u cant guarantee what will happen to the gold during the time gap.~Alex (Clearly done out of desperaton)

Question 98 - Alex Sir Thomas was returning home after a battle when he realised he lost his way. He winded up being in a village where people either tell the truth all the time, lie all the time, or alternate being truthworthy and lieing between every sentence(means 1 sentence he lies and the next he tells the truth). A villager saw him and said:"Good night, ma'am." I need your help, Sir Thomas. My husband did not quarrel with me 3 days ago. My wife had a baby the other day and she refused to tell me whether it's a boy or a girl. She is like me, telling the truth and lying. Now, my wife said:"The baby is of your gender, my husband. And she is quite bubbly I must say." I'm completely smart,see, so i solved her puzzle. Can you get a solution?" Sir Thomas was completely confused. "Oh, and BTW, I can show you the way home if u solve my puzzle." Sir Thomas managed to solve it, but in the process he completely screwed up somewhere and never got home. Why? Clue: His reasoning went like this:"It's clear, the baby's a girl. Your wife claimed that the baby was a boy, yet she proceeded to say the baby was a 'she'.There are no contradictions since you were lying there, therefore it must be a girl." Solution 98 Couldn't that guy e lying abt showing the way homesince they can lie all the time?~Jun Yuan

If I'm not wrong, it should be like this...

"Good night, ma'am." - Lie. (Obviously, SIR THOMAS.) I need your help, Sir Thomas. - Truth (Refer 2 lines below) My husband did not quarrel with me 3 days ago. - Lie (My wife quarreled with me 3 days ago.) My wife had a baby the other day and she refused to tell me whether it's a boy or a girl.- Truth (That's why the man is asking Sir Thomas for 'help'.) She is like me, telling the truth and lying. - Lie (She is not like me, telling the truth and lying.) So, she either tells the truth all the time or tells lies all the time.) Now, my wife said:"The baby is of your gender, my husband. And she is quite bubbly I must say." - Truth (If it is a lie from the woman, the baby is not a boy, and he is not bubbly. Which means, the baby is a girl. If she is telling the truth, she would contradict herself.) I'm completely smart,see, so i solved her puzzle. - Lie (So he is saying that he is completely stupid, so he cannot solve her puzzle.) Can you get a solution?" - Truth (OBVIOUSLY!) "Oh, and BTW, I can show you the way home if u solve my puzzle." - Lie (So that means if Sir Thomas does not solve the puzzle, the man shows the way home. If he does, he will not get shown the way home.)

So to conclude...

He solved his puzzle, so he cannot go home! ~ All typed by Alton

Question 97 - Alex An old water pipe sprung a leak. The leak, at the bottom of the pipe, completely emptied it in 4 hours. A plumber came to repair the pipe. Not noticing the leak, he refilled the pipe and left. Immediately, the pipe sprung a second leak exactly the same as that of the 1st one. Instead of the pipe taking 2 hours to empty, it took 3 instead. Why? Solution 97 There were two leaks~Jun Yuan ... The question stated 'a 2nd leak'. Dont state the obvious, pls.~Alex The second leak was a leak that led water into the pipe. ~ Wei Ren Both leaks were overlapping~Garett All wrong. WR: No leak would fill a pipe GT: The leaks were not overlapping. The 2nd leak was one-quarter from the way down. Thus, in an hour, half of the water would be gone, but the water would have gone down such that the water was not affected by the 2nd leak anymore ~garett I can't follow ur logic. how is 1/4 of the way down supposed to get 1/2 water out? it should only get 1/4 water out...~Alex Maybe it's half way down, I think. the first leak is all the way at the bottom, so the first leak drains 1/4 in an hour, plus the second leak so it would be half in an hour, and the water cannot be affected by the 2nd leak anymore as the water level has already gone down. Thus, the remaining half is drains out after two hour, making it need a total of 3 hours before it empties~Garett
 * sighs* Clue: The leaks were not at the same place. ~Alex

Correct~Alex

Question 96 - Alex Suppose you had a number f in which f+0 is divisible by 1 f+1 is divisible by 1 f+1 is divisible by 2 f+2 is divisible by 3 f+3 is divisible by 5 f+5 is divisible by 8 Find the smallest possible f.

Solution 96 f is definitely an odd number. F+5 = mult of 2 and 3. 3x8=24 so f+5 either = 24x3, 24x8.... Since f+3 = mult of 5, end digit of f must be either 2 or 7. Thus it must be 7. f+2 = mult of 3, and so on.... 67? As 24x1-5 does not end with 7, X 24x2-5 does not end with 5 X 24x3-5 ends with 5 1st Round CORRECT 67+1 = 68 = mult of 2 2nd R(round) C(correct) 67+2 = 69 = mult of 3 3rd R C 67+3 = 70 = mult of 5 4th R C 67+5 = 72 = mult of 8 5th R C Easy :P Jeremy Correct~Alex

Question 95 - Alex Which is smaller, a radian or 1/7 of circle? Solution 95 Same?~Jun Yuan a radian is approx. 7/44 and 1/7 of a circle would equal 6and ttwo-seventh/44 so 1/7 of a circle is smaller~Garett 1 radian = about 57.32 1/7 circle = about 51.43 1/7 of a circle is smaller ~ LBQ Correct~Alex Fine~Jun Yuan

Question 94 - Alex Suppose you had a number f in which... f+1 is divisible by 1 f+2 is divisible by 2 f+3 is divisible by 3 f+5 is divisible by 4 f+8 is divisible by 5 Name the smallest f possible. P.S. f stands for Fibonacci. Solution 94 if f+2 is divisible by 2, f must be even. For f+5 to be divisble by 4, f must be odd, so... IMPOSSIBLE!!! MUAHAHAHAHA!!! hi ~LBQ LOLZ~Alex P.S. It's correct.

Question 93 - Alex Suppose you had a number y in which... y+1 is divisible by 2 y+2 is divisible by 4 y+3 is divisible by 6 y+4 is divisible by 8 y+5 is divisible by 10 y+6 is divisible by 12 y+7 is divisible by 14 y+8 is divisible by 16 y+9 is divisible by 18 y+10 is divisible by 20 y+11 is divisible by 22 y+12 is divisible by 24 Name the smallest y possible. Solution 93 Um...2520?~Jun Yuan I don't think it's possible- if y+1 is divisible by 2, y has to be an odd no, and if y+6 is divisible by 12, y has to also be an even number???~Garett Garett's right. And lolz, 2521 cannot be divided by 2.~Alex Oh yah stupid me~Jun Yuan if y+1 is divisible by 2, y must be odd. For y+2 to be divisble by 4, y must be even, so... IMPOSSIBLE!!! MUAHAHAHAHA!!! (again) hi ~LBQ
 * re-shoots LBQ*I said GT was right.~Alex

<span style="color: #ff0008; font-family: Arial,Helvetica,sans-serif; font-size: 16pt;">Question 92 - Alex Suppose you had a number x in which... x+1 is divisible by 1 x+2 is divisible by 2 x+3 is divisible by 3 x+4 is divisible by 4 x+5 is divisible by 5 x+6 is divisible by 6 x+7 is divisible by 7 x+8 is divisible by 8 x+9 is divisible by 9 x+10 is divisible by 10 x+11 is divisible by 11 x+12 is divisible by 12 Name the smallest x possible. <span style="color: #3366ff; font-family: Arial,Helvetica,sans-serif; font-size: 16pt;">Solution 92

x is 0 ?Or 27220?~Jun Yuan 0 is correct.~Alex(P.S. 27220 is wrong) 0 (obviously) ~ LBQ
 * shoots LBQ* I already put there that it is correct.~Alex

<span style="color: #ff0008; font-family: Arial,Helvetica,sans-serif; font-size: 16pt;">Question 91 - Alex

At a local McDonald's store, two rival teams has agreed to a french-fries eating contest. On the first team was Tom, Marcus, Luke and Fat Harold. On the other team was Jerry, Thomas, Richard, Jack and Sally. Four other people were called on to be witnesses (to ensure the match was fair). One of them, Larry, had betted on Tom's team. Another, Oscar, has betted on Jerry's team. The third claimed he would not bet, and scribbled down a couple of notes. The last person, Kimmy, was undecided. She thinks Tom's team will win, but there are more guys on Jerry's team. Who should she bet on? (**PLEASE SHOW WORKING)** <span style="color: #3366ff; font-family: Arial,Helvetica,sans-serif; font-size: 16pt;">Solution 91 Take Tom's speed as x Marcus: 2x Luke:2x Fat Harold:5x Total for Tom's team: 10x
 * Tom eats 1/2 as fast as Marcus
 * Luke and Marcus eat at the same speed.
 * Fat Harold eat as fast as Tom, Marcus and Luke added together
 * Jerry, Thomas and Richard eat at exactly the same speed as Luke.
 * Jack eats 3 times as fast as Sally and 1/2 as fast as Fat Harold

Jerry's team Jerry:2x Thomas:2x Richard;2x Jack:2.5x Sally: 5 over 6 x total: 9 and 1third x

She shld bet on tom's~GArett

Tom = 6f Marcus = 6f x 2 = 12f Luke = 12f Fat Harold (Fart Harold!) = 6f +12f + 12f = 30f Total = 6f +12f + 12f + 30f = 60f

Jerry = 12f Thomas = 12f Richard = 12f Jack = 30f / 2 =15f Sally = 15f / 3 = 5f Total = 12f + 12f + 12f + 15f + 5f = 56f

She should bet on Jerry's team (if she wants to lose)... If she wants to win, she should bet on Tom's team... (in case you're wondering, f stands for french fries) ~ LBQ(And BQ, that is not funny) Garett wins.~Alex

Tom = 6u Marcus = 12u Luke = 12u Fat Harold = 30u Total = 60u

Jerry = 12u Thomas = 12u Richard = 12u Jack = 15u Sally = 5u Total = 56u

~Keith
 * Seriously, I think that Fat Harold will blow up after the contest.
 * The answer is pretty clear, but I don't like the name "Kimmy", so I suggest she bets £10000 bucks on Jerry's team.

<span style="color: #ff0008; font-family: Arial,Helvetica,sans-serif; font-size: 16pt;">Question 90 - Alex Thomas is at a Pillar X. His best friend, Kim, was walking towards Pillar X at a speed of 13 cm/sec. Kim is currently 130 metres from Pillar X. Kim began walking towards the pillar exactly the same time as Thomas began running towards her. Thomas would turn back and run to the pillar, then turn back and run towards Kim, etc. Kim was however stopped by the teacher when she had walked 39 metres, because she had not done her corrections. Back to the story, Kim then continued walking towards the pillar after her little 'appointment' with the teacher. Thomas would run until Kim reached the pillar. Assuming Thomas ran at 182 cm/sec, how long did he run? <span style="color: #3366ff; font-family: Arial,Helvetica,sans-serif; font-size: 16pt;">Solution 90 How long was Kim stopped? P.S. Kim is sssllllooooowwwwww!!! ~ LBQ 3 min. Sry for the error~Alex

<span style="color: #ff0008; font-family: Arial,Helvetica,sans-serif; font-size: 16pt;">Question 89 - Alex Assume you are at a book fair. You are allowed to buy copies of a book to give out to your friends. If you buy 2, you are automatically given 1. This means you are not allowed to buy books in packs of 2. What is the largest amount of books you CANNOT buy in a SINGLE purchase? Clue 1: You are not allowed to buy in packs of 2, only 1 and 3. Clue 2: You are not allowed to buy 1+1. That is equivalent to buying 2 books. <span style="color: #3366ff; font-family: Arial,Helvetica,sans-serif; font-size: 16pt;">Solution 89 Any number that is one less than a multiple of 3 ~ LBQ in other words you mean its 2. Now stop beating around the Bush.~Alex

<span style="color: #ff0008; font-family: Arial,Helvetica,sans-serif; font-size: 16pt;">Question 88 - Gerry You are in a race in which the starting line is at a certain point on a straight beach. The finish line is in the water. One way to arrive at the finish line is to run 4 kilometers down the beach, make a 90 degree turn and swim 1 kilometer. However, you may cut into the water at any point. You speed on land is 6 k.p.h and you speed in water is 2 k.p.h.. At what point, measured from the starting line, should you cut into the water? <span style="color: #3366ff; font-family: Arial,Helvetica,sans-serif; font-size: 16pt;">Solution 88 So that u hv wat? The slowest time?~Alex

<span style="color: #ff0008; font-family: Arial,Helvetica,sans-serif; font-size: 16pt;">Question 87 - Gerry



Two trains 150 miles apart are traveling toward each other along the same track. The first train goes 60 miles per hour; the second train rushes along at 90 miles per hour. A fly is hovering just above the nose of the first train. It buzzes from the first train to the second train, turns around immediately, flies back to the first train, and turns around again. It goes on flying back and forth between the two trains until they collide, squashing it flat. **If the fly's speed is 120 miles per hour, how far will it travel?** <span style="color: #3366ff; font-family: Arial,Helvetica,sans-serif; font-size: 16pt;">Solution 87 Since the trains crash after 1 hr, the fly traveled 120 miles.~Alex Correct. <span style="color: #3366ff; font-family: Arial,Helvetica,sans-serif; font-size: 16pt;"> <span style="color: #ff0008; font-family: Arial,Helvetica,sans-serif; font-size: 16pt;">Question 86 - Gerry Does this make mathematical sense? In the classic math problem, there are three posts. Disks of different sizes (call the number of disks "n") are placed on the lefthand post, arranged by size with the smallest on top. You are to transfer all the disks to the righthand post in the fewest possible moves, without ever placing a larger disk on a smaller one. One move is considered to be moving one disk from one post to another post.
 * According to the legend of the Tower of Hanoi** (originally the "Tower of Brahma" in a temple in the Indian city of Benares), the temple priests are to transfer a tower consisting of 64 fragile disks of gold from one part of the temple to another, one disk at a time. The disks are arranged in order, no two of them the same size, with the largest on the bottom and the smallest on top. Because of their fragility, a larger disk may never be placed on a smaller one, and there is only one intermediate location where disks can be temporarily placed. It is said that before the priests complete their task the temple will crumble into dust and the world will vanish in a clap of thunder.

<span style="color: #3366ff; font-family: Arial,Helvetica,sans-serif; font-size: 16pt;">Solution 86 18,446,744,073,709,551,615(2^64 - 1)~Alex Correct. <span style="color: #000000; font-family: Arial,Helvetica,sans-serif; font-size: 16pt;"> Correct <span style="color: #ff0008; font-family: Arial,Helvetica,sans-serif; font-size: 16pt;">Question 85 - Gerry
 * How many moves will it take to transfer n disks from the left post to the right post?**

<span style="color: #3366ff; font-family: Arial,Helvetica,sans-serif; font-size: 16pt;">Solution 85 Being given 1 penny first day, 2 pennies second day, four pennies 3rd day, etc.~Alex<span style="color: #3366ff; font-family: Arial,Helvetica,sans-serif; font-size: 16pt;"> Correct<span style="color: #3366ff; font-family: Arial,Helvetica,sans-serif; font-size: 16pt;"> <span style="color: #ff0008; font-family: Arial,Helvetica,sans-serif; font-size: 16pt;">Question 84 - Gerry
 * Which is more: being given one million dollars, or one penny the first day, double that penny the next day, then double the previous day's pennies and so on for a month?**



Solution 84 N=Nickel Q=Quarter 5N+25Q=265 N=Q+11 N+5Q=53 Q+11+5Q=53 6Q=42 Q=7 N=18 18+7=25 Ans: 25~Alex(LOL Took me 2 hours to work out.) <span style="color: #000000; font-family: Arial,Helvetica,sans-serif; font-size: 16pt;"> P.S. Nickel = 5c, Quarter=25c
 * A common algebra problem often goes something like this:**
 * Tony has 11 more nickels than quarters. How many coins does he have if the total value of his coins is $2.65?**

<span style="color: #ff0008; font-family: Arial,Helvetica,sans-serif; font-size: 16pt;">Question 83 - Gerry <span style="color: #000000; font-family: Arial,Helvetica,sans-serif; font-size: 16pt;"> A camel must travel 1000 miles across a desert to the nearest city. She has 3000 bananas but can only carry 1000 at a time. For every mile she walks, she needs to eat a banana. What is the maximum number of bananas she can transport to the city?

<span style="color: #3366ff; font-family: Arial,Helvetica,sans-serif; font-size: 16pt;">Solution 83 <span style="color: #000000; font-family: Arial,Helvetica,sans-serif; font-size: 16pt;"> 2000, she needs 2 more camels...~Alex She won't be able to transport any. If she carries 1000 bananas and walk across 1000miles, she would reach the city but with no bananas, and since she has no bananas, she'll die on the way back home. ~ Wei Ren

Or maybe someone fed her 2k bananas beforehand from another batch, and gave her 1k of the banana, then fed her another 2k of the bananas from yet another batch, then gave her 1k bananas, then when she came back, she was fed yet another 1k bananas from a 4th batch, then they gave her the last 1k. So she can transport 3k, but the bad news is that 5k bananas are wasted LOL.(What camel can carry 1k bananas at a time anyway? And they are fed so much they shouldn't need to eat something every like, 1.6 km)~Alex

<span style="color: #ed332c; font-family: Arial,Helvetica,sans-serif; font-size: 16pt;">Question 82 ~ Nuts (Somehow i cant seem to change the colour. Well, you must highlight it first) <span style="color: #000000; font-family: Arial,Helvetica,sans-serif; font-size: 16pt;">There are 10 bags of coins. (they are open) Nine of them containing 10g coins and one containing 9g coins. Given only a marker and one time at the weighing scale, how are you supposed to find the one with 9g coins? (reason your way out) <span style="color: #3366ff; font-family: Arial,Helvetica,sans-serif; font-size: 16pt;">Solution 82 You can't solve this with only one time at a weighing scale. However, there is a way to solve this. 1. Take 5 of the bags and weigh against the other 5. 2. Take the 5 bags on the lighter side. 3. Take 2 of the bags and weigh against each other. 4. There are 2 possiblities. If one of them is lighter, the lighter bag has 9g coins. If none is lighter, proceed to step 5. 5. Take the 3 remaining bags. Take 2 of them and weigh them against each other. 6. If they are the same, the last bag is the light one. Otherwise, the lighter bag is the light one. Minimum of 2, maximum of 3. And if you know, you can discard the bags that are heavy. No marker at all. ~Alex

Actually you can Here's how: Use the marker and label each bag with numbers 1 - 10 place the number of coins on the bag into one part of the weighing scale (i.e bag labelled 1 would have one ccoin on the weighing scale) Hope that it is an electronic weighing scale(Hey, this IS the 21st century) Then check out how much it weighs (e.g. If it weigh 450g or what) take 550 - (the weigh shown on the display screen) (e.g. 550 - 450) take the answer, and divide it by 10 the bag labelled with that answer would be the one with 9g coins~garett

Yeah, the answer's something like what Garett said. You label the bags with the marker (1-10) then you take 1 coin from the first bag, 2 from the second and so on. you place all the coins that were taken out on the weighing scale (it can be electronic or the other). if the weight's last digit ends with a 9, then its from the first bag, if it's 8 then its the second and blah blah blah ~ Nuts

Question 81 - Alex COMBO BREAKER!!!!!!!!!!!!!!!!!!

There was this robber who was being chased. He came to a town where the roads are very long. The rule was, once you get in you must drive 140 km before turning right. Yeah, do this 4 times and you are back where you started. So how do ya get out? You must drive 12 whole rounds round the town before you get out. It was like midnight though, and the people are so tucked in bed that they wouldn't bother if there was a Formula 1 race at their doorstep. Nor would they be driving. Back to the story, the robber entered town at exactly 11:45 p.m. After driving for 10 minutes at a speed of 165 km/h, the police car came into town, following the robber, at a speed of 169 km/h. Now, here's the interesting bit: For every 5 minutes the robber drove, his speed rises by 4 km/h. The moment his speed is higher than the police, the police will now gain speed at 4km/h per 5 minutes. Once the speed is higher by 4 km/h, the robber raised his speed again. The maximum speed is 215 km/h, after which the car will break down within 20 minutes of driving at that speed. What is the fate of the robber? (a)He gets caught (b)He escapes town (c)His car breaks down, so he is being caught. (d)The police car breaks down, so he escapes town. Also, state the time where the robber gets caught/leaves town. Example: Robber's speed is 165 kmh, police's spd is 169 km/h. 10 minutes later the robber's spd is 173, and 10 minutes later, the robber's spd is still 173,but he now has to raise, because the policeman is at a speed of 177. BTW, this is assuming that the vehicles involved have infinite fuel. Stop asking if this is possible, cos' this is fiction! Solution 81 Firstly, total d = 140x4x12=6720km (215-165)/4=12.5 (max times thief can raise spd) (215-169)/4=11.5 (max times thief can raise spd) 165/20+169/20+173/10+ 169/15+ etcetcetc continue 2mr jeremy